The amount of lactic acid, HC3H5O3, produced in a sample of muscle tissue was analyzed by reaction with hydroxide ion. Hydroxide ion was produced in the sample mixture by electrolysis. The cathode reaction is given below.
2 H2O(l) + 2 e ‾ → H2(g) + 2 OH ‾ (aq)
Hydroxide ion reacts with lactic acid as soon as it is produced. The endpoint of the reaction is detected with an acid-base indicator. It required 106 s for a current of 18.8 mA to reach the endpoint. How many grams of lactic acid (a monoprotic acid) were present in the sample?

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