algebra II-URGENT

the perimeter of a rectangular yard is 270 feet. If its length is 25 feet greater than its width what are the dimensions of the yard

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  1. P=2l+2w
    270=2(w+25)+2w
    270=2w+50+2w
    220=4w
    55=w
    so

    l=w+25
    =55+25
    =80

    Check
    P=2l+2w
    270=2(80)+2(55)
    270=160+110
    270=270

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