Math

When trying to solve
arctan(sqrt 567.2 / -459.6) my answer was -2.96. My teacher said that i handled the radical wrong. She said I have to square both numbers, then add them, and then find the square root. I am confused because you cannot take the square root of -459.6. Please explain.

  1. 👍
  2. 👎
  3. 👁
  1. Im not sure by your equation why you are to follow that process, but if you are to first square the two numbers then you get rid of the -ve

    ie:

    567.2^2 and (-459.6)^2

    i hope this helps

    1. 👍
    2. 👎
  2. arctan(sqrt 567.2 / -459.6)
    = arctan(23.81596/-459.6)
    = arctan(-.051819)
    = -2.97°

    most calculators have been programmed that for any arc(trig function) they will give you the smallest value of rotation from 0,
    so -2.97 would be in the 4th quadrant, coterminal with 360-2.97 or 357.03°

    the tangent is also negative in the 2nd quadrant, so
    the smallest positive answer is 180-2.97 = 177.03°

    check: tan 357.03 = tan 177.03 = .05188
    √567.2/-459.6 = .0518189 , close enough,

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Math:)

    A person is on the outer edge of a carousel with a radius of 20 feet that is rotating counterclockwise around a point that is centered at the origin. What is the exact value of the position of the rider after the carousel rotates

  2. math;)

    Find the unit vector in the direction of u=(-3,2). Write your answer as a linear combination of the standard unit vectors i and j. a. u=-3[sqrt(13)/13]i+2[sqrt(13)/13]j b. u=-3[sqrt(5)/5]i+2[sqrt(5)/5]j c.

  3. algebra

    Simplify: 2 sqrt (3) + 6 sqrt(2) - 4 sqrt(3) + sqrt (2) a) 8 sqrt(2) - 3 sqrt(3) b) 6 sqrt(2) - 8 sqrt(3) c) 5 sqrt(6) d) 7 sqrt(2) - 2 sqrt(3) the answer i picked was d

  4. TRIGONOMETRY

    Evaluate the expressions: a) arctan(-sqrt(3)) a) Arctan(-sqrt(3)) So, I know how to find the answers with a calculator, but how do I find it step by step?

  1. Calculus (Help please!)

    (Re-posting because I think the first one got lost in all the questions) This isn't a test or assignment, it's a review for studying. I'm trying to catch up in my lesson as I have fallen quite behind due to health issues. I'm here

  2. Algebra

    Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work. sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2) x*sqrt 7x-49*x ^^^ would this be my final answer?

  3. limiting position of the particle

    A particle moves along the x axis so that its position at any time t>= 0 is given by x = arctan t What is the limiting position of the particle as t approaches infinity? Answer is pi/2 How do I solve this? Thanks a lot. You want

  4. calculus

    For x>0 find and simplify the derivative of f(x)= arctan(x) + arctan(1/x). I've done the problem a few times and I keep getting (1)/(1+(x)^2)+(1)/(1+(1/(1/x)^2))(-x)^-2 but something about the answer is wrong and I cannot figure

  1. Inequality

    When I solve the inquality 2x^2 - 6 < 0, I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or (-infinity, sqrt(3))? Why? Thanks. So would this work? abs x < ( sqrt 3 ) or - sqrt 3

  2. calculus

    Find the exact value of: cos(arctan(2) + arctan(3)) Please explain how you got your answer. I have the answer, but I don't know how to get to it.

  3. trigonometry

    4 arctan(1/3)+4 arctan(1/4)+4 arctan(2/9)=pi how do i prove it but without using this formula arctan(x)+arctan(y) = arctan( x+y/1+xy)

  4. Pre Cal.

    Evaluate tan(cos^(-1)(ã3/2 )+tan^(-1)(ã3/3))? arccos(sqrt(3) / 2) = pi / 6 arctan(sqrt(3) / 3) = pi / 6 tan(pi / 6 + pi / 6) = tan(pi / 3) = sqrt(3).

You can view more similar questions or ask a new question.