physics

point a is located 0.25 m away from a charge of -2.1 x 10 -9 C. point b is located 0.50 m away from the charge. what is the electric potential difference Vb - Va between these two points?

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asked by kim
  1. k q[(1/X1) - (1/X2)], where
    k = Coulomb's Law constant,
    8.99 × 10^9 N*m^2/C^2
    X1 = 0.50 m
    X2 = 0.25 M
    q = 2.1 x 10^-9 C

    The answer will be in N*m or Joules

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    posted by drwls

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