Oxygen gas can be generated by heating KClO3 in the presence of a catalyst.
KClO3 ----> KCl + O2 (unbalanced)
What volume (in L) of O2 gas will be generated at T = 25 oC and P = 10.26x104 Pa from 1.28 g KClO3?

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  1. 1. Balance the equation.
    2. Convert 1.28 g KClO3 to moles. moles = grams/molar mass.
    3. Using the coefficients in the balanced equation, convert moles KClO3 to moles O2.
    4. Convert moles O2 to L using PV = nRT. Don't forget to convert Pa to atm and T to Kelvin.

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