240 is the sum of two numbers in which the larger number is 6 less than twice the smaller number what are the two numbers
Let x be the bigger number
x + y = 240
x = 2y - 6
Solve the two simultaneous equations.
x = 240 - y = 2y -6
3y = 246
y = 82
x = ?
the sum of two numbers is 240 the larger number is 6 less than twice the smaller. what are the two number.
what is the value of x
what is the value of x in algrebra
To solve this question, we can set up an equation based on the given information.
Let's assume the smaller number is represented by x.
According to the problem, the larger number is 6 less than twice the smaller number. So the larger number would be 2x - 6.
We are also given that the sum of these two numbers is 240.
Hence, we can create the equation:
x + (2x - 6) = 240
Now, we can solve for x.
Combining like terms on the left side of the equation:
3x - 6 = 240
Adding 6 to both sides of the equation to isolate 3x:
3x = 246
Dividing both sides of the equation by 3 to solve for x:
x = 82
Therefore, the smaller number is 82.
Now, we can substitute the value of x back into the equation to find the larger number:
2x - 6 = 2(82) - 6 = 164 - 6 = 158
Therefore, the two numbers are 82 and 158.