What is the final volume of 880. mL of hydrogen gas at 335 mm Hg if the pressure is increased to 735 mm Hg? Assume the temperature and the amount of gas are held constant.
i can somewhat help with this:
temperature is not important so forget that part teke ur ml and convert to L by dividing 880 by 1000 that's as far as I know how to go hope it helps a lil bit ...
P1V1 = P2V2
To find the final volume of hydrogen gas, we can use Boyle's Law, which states that the product of pressure and volume is constant for a given amount of gas at constant temperature.
Boyle's Law: P₁V₁ = P₂V₂
Where:
P₁ = Initial pressure
V₁ = Initial volume
P₂ = Final pressure
V₂ = Final volume
In this case, the initial pressure (P₁) is 335 mm Hg, and the initial volume (V₁) is 880 mL. The final pressure (P₂) is 735 mm Hg, and we need to find the final volume (V₂).
We can rearrange Boyle's Law to solve for V₂:
V₂ = (P₁ * V₁) / P₂
Substituting the given values:
V₂ = (335 mm Hg * 880 mL) / 735 mm Hg
Now let's do the calculation:
V₂ = (294,800 mm Hg * mL) / 735 mm Hg
Canceling out the units of mm Hg:
V₂ = 400 mL
Therefore, the final volume of the hydrogen gas is 400 mL when the pressure is increased to 735 mm Hg, assuming the temperature and the amount of gas are held constant.