2^(2x+13) = 3^(x-45)
hint: take the logarithm
2x+13 log 2 = x -45 log 3
subtract x - 45 log 3 or
subtract 2x + 13 log 2
i subtracted x - 45 log
i got x + 58.. then do i subtract the log 3
? x + 58 log 1
take that back... subtract only x and then do the rest.
so now i have.. x+13 log 2=-45 log 3..
(2x+13) log 2 = (x -45) log 3
2x(log2 + 13log2 = x(log3) - 45log3
2x(log2) - x(log3) = -45log3 - 13log2
x(2log2 - log3) = -45log3 - 13log2
x = (-45log3 - 13log2)/(2log2 - log3)
x = -203.17