A shaft which rotates at 300r/min is uniformly accelerated to 600r/min in 15secs.Calculate:

(a) The angular acceleration.
(b) The angle through which the shaft has turned during the acceleration.

angular acceleration= change in ang velociyt/time= 300rev/min/.25min=1200rev/min^2

you may want to change the units.

displcement= wi*t+1/2 angacc*time^2=
=300rev/min*.25min+ 1/2*1200rev/min^2*(1/4 min)^2

To solve this problem, we'll need to use the formulas for angular acceleration and the angle through which an object has turned. Here's how we can find the answers to both parts of the problem:

(a) The angular acceleration can be calculated using the formula:

Angular acceleration (α) = (Final angular velocity - Initial angular velocity) / Time

Given that the initial angular velocity (wi) is 300 r/min, the final angular velocity (wf) is 600 r/min, and the time (t) is 15 seconds, let's calculate the angular acceleration (α):

α = (600 r/min - 300 r/min) / 15 s
= 300 r/min / 15 s
= 20 r/min²

Therefore, the angular acceleration is 20 r/min².

(b) The angle through which the shaft has turned during the acceleration can be determined using the formula:

θ = (1/2) * α * t²

Given that the angular acceleration (α) is 20 r/min² and the time (t) is 15 seconds, let's calculate the angle (θ):

θ = (1/2) * 20 r/min² * (15 s)²
= (1/2) * 20 r/min² * 225 s²
= 2250 r

Therefore, the angle through which the shaft has turned during the acceleration is 2250 radians.