For the cell: C(s) C+(aq) B+(aq) B(s).
Metal ______ is the "negative" electrode.
is it C(s)
yes; however, you would have done better to write it in standard form. It took a few minutes for me to figure out that this was a cell.
C(s)|C^+||B^+|B(s) is what I assume you meant and my response is based on that interpretation.
so do i put the answer as C(s) including the state
Yes, C(s) is the negative electrode. The reaction at this electrode is
C(s) ==> C^+ + e
It is giving off electrons which is why it has a negative charge.
Yes, the metal C(s) is the "negative" electrode in this cell.
To determine this, we can use a few guidelines:
1. The "negative" electrode, also known as the anode, is where oxidation occurs. In other words, it is where electrons are lost from the substance.
2. In this cell, C(s) is written first on the left side, which indicates that it is the starting material for the electrode.
3. On the right side, you have C+(aq), which indicates that C(s) is being oxidized to form C+(aq). This suggests that electrons are being lost from C(s), making it the anode or "negative" electrode.
So, based on these guidelines, C(s) is the "negative" electrode in this cell.