Simplify.
1.(-15xy^4)(-1/3xy3)
Is the answer for number 1 = -15x^6y^1?Thanks
Express the area of each figure as a monomial.
1.A circle with the radius of 5x^3.
how would I solve this problem?
I don't get anything close to that on 1.
-15/-3 * x*x * y^4 *y1
area= PI radius^2=PI(5x^3)^2=25 PI x^6
1. No, that is not the answer.
If you are multiplying the terms in parentheses, you add exponents.
For the constant coefficient,
(-15) x (-1/3) = 5
1. Substitute 5x^3 for r in
Area = pi*r^2
To simplify the expression (-15xy^4)(-1/3xy^3), you need to multiply the coefficients and add the exponents of the variables.
First, multiply the coefficients:
-15 * (-1/3) = 5
Next, multiply the variables. In this case, you need to multiply the x terms and the y terms separately:
x * x = x^2
y^4 * y^3 = y^(4+3) = y^7
Combining the coefficients and variables, the simplified expression is:
5x^2y^7
Therefore, the answer to question 1 is not -15x^6y^1, but 5x^2y^7.
Now, for the second question, to express the area of the circle as a monomial, you need to use the formula for the area of a circle: A = πr^2, where r is the radius.
Given that the radius of the circle is 5x^3, you can substitute this value into the formula to find the area:
A = π(5x^3)^2
= π(25x^6)
Thus, the area of the circle with a radius of 5x^3 can be expressed as the monomial 25πx^6.