how much heat dows a 23.0g ice cube absorb as its temp increases from -17.4deg C to 0.0deg C?
q = mass ice x specific heat ice x (Tfinal-Tinitial)
To determine the amount of heat absorbed by the ice cube, we can use the equation:
Q = mcΔT
Where:
Q represents the amount of heat absorbed
m is the mass of the ice cube (23.0g)
c is the specific heat capacity of ice (2.09 J/g°C)
ΔT is the change in temperature (0.0°C - (-17.4°C))
First, let's calculate the change in temperature:
ΔT = 0.0°C - (-17.4°C)
ΔT = 17.4°C
Now we can substitute the values into the equation and calculate the amount of heat absorbed:
Q = (23.0g) * (2.09 J/g°C) * (17.4°C)
Q ≈ 794.5 J
Therefore, the ice cube absorbs approximately 794.5 joules of heat as its temperature increases from -17.4°C to 0.0°C.