1. when sodium is combined with water, sodium hydroxide and hydrogen gas are produced. How many moles of sodium do you need to make 4.0 mol of hydrogen gas?

2.when aluminium reacts with sulfuric acid, aluminium sulfate and hydrogen gas are produced. How many moes of sulfuric acid will react with 18 moles of aluminium?
3. when phosphorus is combined with oxygen, tetraphosphorus decaoxide is produced
a. what mass of phosphorus is needed to produce 3.25 mol of P4O10
b.if 0.489 mol of phosphorus is used how many grams of oxygen is also used
c.if 0.489 mol of phosphorus is used how many grams of P4O10 are produced

I will be happy to critique your work. Start with a balanced chemical equation.

To answer these questions, we need to use the balanced chemical equations and the concept of mole ratios. Let's break down each question step by step:

1. Sodium reacts with water to produce sodium hydroxide and hydrogen gas. The balanced equation for this reaction is:
2Na + 2H2O -> 2NaOH + H2

From the equation, we can see that for every 2 moles of sodium reacting, we get 1 mole of hydrogen gas. We are given that we want 4.0 moles of hydrogen gas, so we need to determine how many moles of sodium are required.

To find the number of moles of sodium, we need to use the mole ratio from the balanced equation. The ratio is 2 moles of sodium to 1 mole of hydrogen gas. Therefore, for every 1 mole of hydrogen gas, we need 2 moles of sodium.

Since we want 4.0 moles of hydrogen gas, we need to multiply this by the ratio:
4.0 moles H2 * (2 moles Na / 1 mole H2) = 8.0 moles of sodium

So, to produce 4.0 moles of hydrogen gas, we need 8.0 moles of sodium.

2. In this question, we are given that aluminum reacts with sulfuric acid to produce aluminum sulfate and hydrogen gas. The balanced equation is:
2Al + 3H2SO4 -> Al2(SO4)3 + 3H2

From the equation, we can see that for every 2 moles of aluminum reacting, we get 3 moles of sulfuric acid. We are given that we want to react with 18 moles of aluminum, so we need to determine how many moles of sulfuric acid are required.

To find the number of moles of sulfuric acid, we need to use the mole ratio from the balanced equation. The ratio is 3 moles of sulfuric acid to 2 moles of aluminum. Therefore, for every 2 moles of aluminum, we need 3 moles of sulfuric acid.

Since we want to react with 18 moles of aluminum, we need to multiply this by the ratio:
18 moles Al * (3 moles H2SO4 / 2 moles Al) = 27 moles of sulfuric acid

So, to react with 18 moles of aluminum, we need 27 moles of sulfuric acid.

3. In this question, we are given that phosphorus reacts with oxygen to produce tetraphosphorus decaoxide (P4O10).

a. To determine the mass of phosphorus needed to produce 3.25 moles of P4O10, we need to know the molar mass of P4O10. The molar mass of P4O10 is calculated by adding the atomic masses of phosphorus (P) and oxygen (O).

The atomic mass of phosphorus (P) is 31.0 g/mol, and the atomic mass of oxygen (O) is 16.0 g/mol. Since there are 4 phosphorus atoms and 10 oxygen atoms in each molecule of P4O10, the molar mass is:
4(31.0 g/mol) + 10(16.0 g/mol) = 124.0 g/mol + 160.0 g/mol = 284.0 g/mol

To find the mass of phosphorus needed, we can use the mole ratio from the balanced equation. From the formula P4O10, we can see that there are 4 moles of phosphorus for every 1 mole of P4O10.

Therefore, the mass of phosphorus needed can be calculated as:
3.25 moles P4O10 * (4 moles P / 1 mole P4O10) * (31.0 g / 1 mol) = 403.75 g of phosphorus

b. To determine the number of grams of oxygen used when 0.489 mol of phosphorus is used, we can use the mole ratio from the balanced equation. From the formula P4O10, we can see that there are 10 moles of oxygen for every 1 mole of P4O10.

Therefore, the number of grams of oxygen used can be calculated as:
0.489 moles P * (10 moles O / 1 mole P4O10) * (16.0 g / 1 mol) = 78.24 g of oxygen

c. To determine the number of grams of P4O10 produced when 0.489 mol of phosphorus is used, we can use the mole ratio from the balanced equation. From the formula P4O10, we can see that there is 1 mole of P4O10 for every 4 moles of phosphorus.

Therefore, the number of grams of P4O10 produced can be calculated as:
0.489 moles P * (1 mole P4O10 / 4 moles P) * (284.0 g / 1 mol) = 34.03 g of P4O10

So, when 0.489 moles of phosphorus is used, 78.24 grams of oxygen are used, and 34.03 grams of P4O10 are produced.