Mr. Adams has a box containing 14 coins. The coins are either quarters, nickels, or dimes. In the box are 4 quarters. There are 4 times as many dimes as nickels. How many dimes are in the box?
I just need the equation set up and I can then take it from there.
Thanks,
guitarman
14=4+D+N
but D=4N so
14=4+4N+N
5N=10 solve for N, then D
Thank you Bob.
I got dimes = 8.
To solve this problem, we can set up two equations based on the given information.
Let's use the variables:
q = number of quarters
n = number of nickels
d = number of dimes
Given information:
1) The total number of coins is 14: q + n + d = 14
2) There are 4 quarters: q = 4
3) There are 4 times as many dimes as nickels: d = 4n
With these equations, we can solve for the number of dimes.
Substituting q = 4 and d = 4n into the first equation gives us:
4 + n + 4n = 14
Combining like terms, we get:
n + 4n = 14 - 4
5n = 10
Dividing both sides by 5, we find:
n = 2
Finally, substituting n = 2 into d = 4n:
d = 4 * 2
d = 8
Therefore, there are 8 dimes in the box.