what is the solution of the following linear system?
5x - 2y = 15
5/3x - y = 5
a)(-2,1)
b) none
c)(3,0)
d) inifinite number if solutions
If you want to learn the subject, you should learn how to solve the equations. You or others with different screen names have been submitting these simple multiple choice problems all day. In one case a wrong quess was made.
At the very least, try the different x,y combinations and see which one works. One of them does.
Learn the technique of substitution and you can solve these problems yourself. You could, for example, substitute (5/3)x - 5 for y in the first equation.
That would give you
5x - (10/3)x +10 = 15
(5/3)x = 5
x = (3/5)* 5 = 3
To find the solution of the linear system, we can use the method of substitution or the method of elimination.
Let's use the method of elimination:
1. Multiply the second equation by 3 to eliminate the fraction:
3 * (5/3x - y) = 3 * 5
5x - 3y = 15
Now we have a new system:
5x - 2y = 15
5x - 3y = 15
2. Subtract the second equation from the first equation:
(5x - 2y) - (5x - 3y) = 15 - 15
5x - 2y - 5x + 3y = 0
y = 0
3. Substitute the value of y (which is 0) back into one of the original equations:
5x - 2(0) = 15
5x = 15
x = 3
So the solution to the linear system is (3, 0).
Therefore, the answer is (c) (3, 0).