what is the solution if the following system of equations?
y = 2x + 10
3y = -4x
a)(5,1)
b)(4,-3)
c)(1,5)
d)(-3,4)
D is correct. I had trouble solving this, so I just plugged the choices into the equation and D is the only one that works.
Substitute 2x + 10 for y in the second equation and solve for x. Put that value in the first equation to find y. Check by putting both values in the second equation.
Sorry for spelling.
To find the solution to the given system of equations, we will solve them simultaneously. Let's start by substituting the value of y from the first equation into the second equation:
3y = -4x
3(2x + 10) = -4x
Simplifying the equation, we get:
6x + 30 = -4x
Now, let's isolate x by moving -4x to the other side:
6x + 4x = -30
10x = -30
Dividing both sides by 10:
x = -3
Now that we have the value of x, we can substitute it back into one of the original equations to find y. Let's use the first equation:
y = 2x + 10
y = 2(-3) + 10
y = -6 + 10
y = 4
So, the solution to the given system of equations is (x, y) = (-3, 4).
Looking at the answer choices, the correct solution is (d) (-3, 4).