what is the solution of the following system of equations?
y = -2/3x
y = 1
a)(1,-2/3)
b)(-3/2,1)
c)(-2,3)
d)(1,-3)
You have already been told that y = 1.
You also know that x = -(3/2)y, so x = -3/2
(-3/2, 1) is a way of writing that x= -3/2 and y = 1
Therefore the answer is (b)
Wow this question is old as hell
To find the solution of the system of equations, we need to solve for the values of x and y that satisfy both equations.
Given:
Equation 1: y = -2/3x
Equation 2: y = 1
To determine the values of x and y that satisfy both equations, we can equate Equation 1 and Equation 2:
-2/3x = 1
To isolate x, we multiply both sides of the equation by -3/2:
-2/3x * -3/2 = 1 * -3/2
x = -3/2
Now that we have the value of x, we can substitute it back into one of the equations to find the corresponding value of y. Let's use Equation 2:
y = 1
Therefore, the solution to the system of equations is x = -3/2 and y = 1.
The correct answer is b) (-3/2, 1).
To find the solution of the system of equations, we need to find the values of x and y that satisfy both equations simultaneously.
Equation 1: y = -2/3x
Equation 2: y = 1
We can substitute Equation 2 into Equation 1 to solve for x:
1 = -2/3x
Let's solve for x:
Multiply both sides of the equation by 3/2 to get rid of the fraction:
(3/2) * 1 = (3/2) * (-2/3x)
3/2 = -1x
3/2 = -x
Divide both sides of the equation by -1:
(-3/2) / (-1) = x
3/2 = x
Now, we have found the value of x, which is 3/2.
To find the value of y, we can substitute this value of x into any of the original equations. Let's use Equation 2:
y = 1
So, the solution to the system of equations is (3/2, 1).
None of the options provided match the solution we found, so none of them are correct.