How much water must be added if you want to make 1L of solution that is 6M, into a 3M solution
mL x M = mL x M.
1000 mL x 6M = mL x 3M
mL = (1000 x 6)/3 = 2000 mL. Therefore, add 1000 mL
To determine the amount of water that needs to be added to a 6M solution to obtain a 3M solution, you first need to understand the concept of molarity and how it relates to dilution.
Molarity (M) is a measure of concentration, defined as the number of moles of solute per liter of solution. In this case, you are starting with a 6M solution, which means there are 6 moles of solute per liter of solution.
The formula for dilution is: C1V1 = C2V2
where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
In this case, we are given:
C1 = 6M (initial concentration)
V1 = 1L (initial volume)
C2 = 3M (final concentration)
V2 = ? (final volume)
We can rearrange the formula to solve for V2:
V2 = (C1 * V1) / C2
Substituting the given values:
V2 = (6M * 1L) / 3M
Calculating:
V2 = 2L
Therefore, to make a 3M solution from a 6M solution, you would need to add 2 liters of water.