a 1.00 L aqueous solution contained 5.80 g of NaOH. what is the pH of the solution?

Can someone help me out with the setup of this?

M = moles/L

moles = grams/molar mass
moles NaOH = 5.80 g/40 = moles and that will be the molarity since it is in 1 L of solution.
Then pOH = -log(OH^-) and pH + pOH = 14.

okay, can the ph go over 14?

5.80/40=1.45
-log(1.45)= -0.16
14-^-0.16= 14.16
i must be doing something wrong

No, you're doing it right. It's the problems that make it do this. The pH can be negative numbers and if these are pOH numbers, then pH will be larger than 14. In real world chemistry, it isn't the concn that is plugged into that formula but the activity of the solution. The activity approaches the concn at very very dilute solutions but at higher concns there are large deviations from so-called ideal behavior. Also, water has a leveling effect so that, in theory at least, 14 is the maximum number. Neither activity nor leveling effect get much discussion in beginning courses. I wouldn't let this bother me. Just go ahead and calculate using pH = -log(H^+) and pH pOH = 14.

5.80/40 is 0.145

Hey there! Sure, I'd be happy to help you out with this!

To find the pH of a solution, we first need to calculate the concentration of hydroxide ions (OH-) in the solution. We can do this by finding the number of moles of NaOH in the solution, and then dividing it by the volume of the solution in liters.

First, let's convert the mass of NaOH to moles. The molar mass of NaOH is 22.99 g/mol for sodium (Na), plus 16.00 g/mol for oxygen (O), plus 1.01 g/mol for hydrogen (H):

Molar Mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Now, we can calculate the number of moles of NaOH:

Moles of NaOH = Mass of NaOH / Molar Mass of NaOH

Moles of NaOH = 5.80 g / 40.00 g/mol

Moles of NaOH ≈ 0.145 mol

Since the solution is 1.00 L, the concentration of NaOH in the solution is:

Concentration of NaOH = Moles of NaOH / Volume of Solution

Concentration of NaOH = 0.145 mol / 1.00 L

Concentration of NaOH = 0.145 M

Finally, to find the concentration of hydroxide ions (OH-) in the solution, we can assume that NaOH completely dissociates in water, meaning that every mole of NaOH produces one mole of hydroxide ions:

Concentration of OH- = Concentration of NaOH = 0.145 M

Now, we can find the pOH (the negative logarithm of the concentration of hydroxide ions):

pOH = -log[OH-]

pOH = -log(0.145)

pOH ≈ 0.84

Since pH + pOH = 14, we can find the pH of the solution:

pH = 14 - pOH

pH = 14 - 0.84

pH ≈ 13.16

So, the pH of the solution is approximately 13.16. Remember, this is a basic solution, not acidic!

I hope this helps, and don't hesitate to reach out if you have any more questions!

To find the pH of the solution, we need to understand that NaOH is a strong base that dissociates completely in water. This means that all of the NaOH is converted into Na+ ions and OH- ions in the solution.

First, we need to calculate the number of moles of NaOH present in the solution. We can use the equation:

moles = mass / molar mass

The molar mass of NaOH is calculated by adding the atomic masses of Na, O, and H. So, 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol.

Using the given mass of 5.80 g, we can calculate the number of moles:

moles = 5.80 g / 40.00 g/mol

Next, we need to determine the concentration of hydroxide ions (OH-) in the solution. Since NaOH is a strong base, it dissociates completely to produce one mole of OH- ions for every mole of NaOH. Therefore, the concentration of OH- ions is the same as the concentration of NaOH in moles per liter.

Since the solution has a volume of 1.00 L, the concentration of OH- ions is:

concentration = moles / volume

Substituting the values we calculated:

concentration = (5.80 g / 40.00 g/mol) / 1.00 L

Now that we have the concentration of OH- ions, we can calculate the pOH of the solution using the equation:

pOH = -log[OH-]

Finally, we can find the pH of the solution using the equation:

pH = 14 - pOH

Remember to take the negative logarithm of the concentration and use base 10 logarithms.

By following these steps, you should be able to determine the pH of the given solution.