Which product is formed by beta emission from phosphorus -32? The atomic number of phosphorus is 15.
A)28 Al 13
B)30 Al 13
C)32 S 16
D)32 P 15
E)33 P 15
Written this way, 15P^32 means 15 atomic number (which is phosphorus) and ^32 means mass number.
15P^32 ==> -1e^0 + X
The subscripts must add up on both sides as does the mass number; therefore, X will be 16X^32. What is 16X^32.
The product formed by beta emission from phosphorus-32 (atomic number 15) is the isotope of sulfur with mass number 32 (atomic number 16).
Therefore, the correct answer is C) 32 S 16.
To determine the product formed by beta emission from phosphorus-32 (P-32), we need to identify the change that occurs during beta emission.
During beta decay, a neutron in the nucleus of an atom is converted into a proton, and an electron (beta particle) is emitted. Therefore, the mass number remains the same, but the atomic number increases by 1.
P-32 has an atomic number of 15. So, if a beta particle is emitted from P-32, the resulting product will have an atomic number of 15 + 1 = 16.
Now, let's analyze the options:
A) 28 Al 13: This option has an atomic number of 13, which is not the expected increase of 1 from 15. Therefore, it is not the correct answer.
B) 30 Al 13: Similar to Option A, this option also has an atomic number of 13, which is not the expected increase. Therefore, it is not the correct answer.
C) 32 S 16: This option has an atomic number of 16, which matches the expected increase of 1 from 15. Therefore, it could potentially be the correct answer.
D) 32 P 15: This is the original isotope of phosphorus (P-32) and not the product of beta emission. Therefore, it is not the correct answer.
E) 33 P 15: This option has an atomic number of 15, which is not the expected increase. Therefore, it is not the correct answer.
Based on our analysis, the correct answer is option C) 32 S 16, as it matches the expected increase in atomic number from P-32.