What is the pH of a solution in which [H30+] = 1.2 x 10^-3 M?
A)1.20
B)2.92
C)11.08
D)12.80
E)8.33 x 10-12
The pH of a solution can be calculated by taking the negative log (base 10) of the hydrogen ion concentration.
In this case, [H30+] = 1.2 x 10^-3 M.
Using the formula,
pH = -log[H30+]
pH = -log(1.2 x 10^-3)
pH = -log(1.2) - log(10^-3)
pH = -log(1.2) - (-3)
pH ≈ -0.08 - (-3)
pH ≈ 2.92
Therefore, the pH of the solution is approximately 2.92.
The correct answer is B) 2.92.
To determine the pH of a solution, you can use the equation:
pH = -log[H3O+]
Given that [H3O+] = 1.2 x 10^-3 M, you can substitute this value into the equation:
pH = -log(1.2 x 10^-3)
To evaluate this, you can use the logarithm (log) function on a calculator or a scientific calculator.
Make sure to use the base 10 logarithm (log base 10) function. On most calculators, this is labeled as "log" or "log10".
Using the equation, the pH of the solution is approximately 2.92.
Therefore, the answer is B) 2.92.