Use the formula 4.9t^2 +vot=s, where t is the time in seconds, vo is the initial velocity, and s is the distance in meters.
Approximately how far will an object fall in 4 seonds, if it is thrown downward at an initial velocity of 20 meters per second (vo) from a helicopter?
Is this right?
4.9(t)^2+vot=s
4.9(4)^2+20(4)=s
(4.9)(16)+80=s
78.4 +80=s
158.4 meters
yes, correct.
Thank you
Yes, your calculation is correct. According to the given formula, if an object is thrown downward from a helicopter with an initial velocity of 20 meters per second and we plug in t = 4 seconds, the distance it will fall can be calculated as follows:
s = 4.9t^2 + vot
s = 4.9(4)^2 + 20(4)
s = (4.9)(16) + 80
s = 78.4 + 80
s = 158.4 meters
So, the object will fall approximately 158.4 meters in 4 seconds.
Yes, your calculations are correct. According to the formula 4.9t^2 + vot = s, where t is the time in seconds, vo is the initial velocity, and s is the distance in meters, we can substitute the given values:
t = 4 seconds (time)
vo = 20 meters per second (initial velocity)
Plugging these values into the formula, we get:
4.9(4)^2 + 20(4) = s
4.9(16) + 80 = s
78.4 + 80 = s
158.4 = s
Therefore, an object falling for 4 seconds with an initial velocity of 20 meters per second will fall approximately 158.4 meters.