Using only these numbers once for each answer 8,1,4,3,7 the product of two 2 digit numbers plus a number is 3,355. What are the numbers?
78*43+1=3355
To solve this problem, we need to find two two-digit numbers and one single-digit number such that their product, when added together, equals 3,355.
Let's start by finding the two-digit numbers. We know that the product of these numbers is a four-digit number, so it must be greater than 3,355.
To get a rough estimate of the range of values we need to consider, we can take the square root of 3,355, which is approximately 57.99. This tells us that the numbers we are looking for are somewhere between 58 and 99.
Now, let's multiply various two-digit numbers within this range to see if any combination gives us a product close to 3,355. By trying different combinations, we find that the closest we can get is:
84 * 47 = 3,948
This gives us a product greater than 3,355. So, we need to find a way to reduce the product to 3,355 by subtracting a single-digit number.
Now, let's consider the single-digit number. We have the following numbers available: 8, 1, 4, 3, 7. We need to find a number to subtract from the product 3,948 in order to obtain 3,355.
To find this number, we can try subtracting each available single-digit number from 3,948 and check if the result equals 3,355:
3,948 - 8 = 3,940 (not equal to 3,355)
3,948 - 1 = 3,947 (not equal to 3,355)
3,948 - 4 = 3,944 (not equal to 3,355)
3,948 - 3 = 3,945 (not equal to 3,355)
3,948 - 7 = 3,941 (not equal to 3,355)
None of the subtractions gave us the desired result of 3,355. This means that it is not possible to find two two-digit numbers and one single-digit number from the given set of numbers (8, 1, 4, 3, 7) that satisfy the condition mentioned in the problem.