Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.
How does this translate into an algebra statement?
im guessing but 7(2x-6)=x-1
7(6-2N)=N-1
To translate the given information into an algebraic statement, let's break it down step by step:
Step 1: Let's assume the number we are trying to find is 'x'.
Step 2: "The difference of six and a twice a number" can be written as (2x - 6). Here, we are doubling 'x' (2x) and subtracting 6 from it to calculate the difference with 6.
Step 3: "Seven times the difference of six and a twice a number" is then 7 * (2x - 6).
Step 4: "The same number decreased by one" can be written as (x - 1).
Step 5: According to the given information, "Seven times the difference of six and a twice a number yields the same result as the same number decreased by one." This can be expressed as an algebraic equation: 7 * (2x - 6) = (x - 1).
So, the algebraic statement for the given information is: 7 * (2x - 6) = (x - 1).