Write a net equation for the reaction between aqueous solutions of NaHSO4 and NaCN.
see below
To write the net equation for a reaction, we need to first understand the reactants and products involved. In this case, the reactants are aqueous solutions of NaHSO4 (sodium hydrogen sulfate) and NaCN (sodium cyanide).
To write the net equation, we will begin by identifying the dissociation of the compounds in water. When NaHSO4 dissolves in water, it dissociates into the respective ions:
NaHSO4 (aq) → Na+ (aq) + HSO4- (aq)
Similarly, NaCN dissociates into its respective ions:
NaCN (aq) → Na+ (aq) + CN- (aq)
Now, we need to determine if there are any spectator ions that are present both as reactants and products. In this case, Na+ is present on both sides. Since it does not undergo any chemical change, we can eliminate it as a spectator ion.
The remaining ions are HSO4- and CN-. To form a product, these ions need to combine. However, the reaction between these two ions does not directly produce a compound that is insoluble or a gas, which would indicate a precipitate or a gas-forming reaction. Therefore, it is safe to assume that no reaction occurs between HSO4- and CN-.
Hence, the net equation for the reaction between aqueous solutions of NaHSO4 and NaCN can be written as:
NaHSO4 (aq) + NaCN (aq) → No reaction
It is important to note that in certain cases, if the reaction occurs in a specific condition or with a catalyst, a different net equation may be formed. However, in the given scenario, no reaction occurs.