Write a net equation for the reaction between aqueous solutions of NaNO2 and NaH2PO4.

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To write the net equation for the reaction between aqueous solutions of NaNO2 (sodium nitrite) and NaH2PO4 (sodium dihydrogen phosphate), we need to first identify the chemical formulas of the reactants and products.

The reactants are NaNO2 and NaH2PO4. Their chemical formulas tell us that they are composed of the following ions:

- NaNO2: Sodium ion (Na+) and nitrite ion (NO2-)
- NaH2PO4: Sodium ion (Na+) and dihydrogen phosphate ion (H2PO4-)

To determine the products of the reaction, we need to check the solubility rules to see if there is a possible precipitation or formation of a gas. However, both sodium nitrite (NaNO2) and sodium dihydrogen phosphate (NaH2PO4) are soluble in water, which means they will dissociate into their constituent ions without forming a solid or a gas.

When we combine the reactant ions, we have Na+ from both reactants, so the sodium ions will not be involved in the net equation. The remaining ions are NO2- and H2PO4-.

To balance the charges, we need two nitrite ions (NO2-) to combine with one dihydrogen phosphate ion (H2PO4-). Therefore, the net equation for the reaction can be written as:

2 NO2- + H2PO4- → NO2- + HPO42-

In this equation, the sodium ions are omitted from both sides because they are spectator ions and do not participate in the reaction.

So, the net equation for the reaction between aqueous solutions of NaNO2 and NaH2PO4 is 2 NO2- + H2PO4- → NO2- + HPO42-.