I have a diagram that I have to identify for homework. The structure shows an "R" connected with single bond to carbon(in the middle)-which in turn is connected to OH with single bond.-The carbon in the middle has a double bond with Oxygen on the top. The possible answers are carboxylic acid, alcohol, alkane or amine.

Thank you

I think you have described a carboxylic acid. Does it look this way?

RCOOH but the middle O has a double bond to C. Let me try to find a diagram on the internet and I'll post that.

http://en.wikipedia.org/wiki/Carboxylic_acid

If this isn't it repost and let me know.

Thank you-that's it-i really appreciate it

Based on the description you provided, the structure you have described corresponds to an alcohol. Here's how you can determine the answer on your own:

To identify the functional group present in the diagram, you need to understand the chemical properties and structure of each of the given options:

1. Carboxylic acid: A carboxylic acid is characterized by the presence of a carbonyl group (C=O) and a hydroxyl group (-OH) on the same carbon atom. However, in the diagram you shared, there is no carbonyl group present.

2. Alcohol: An alcohol is characterized by the presence of a hydroxyl group (-OH) attached to a carbon atom. In the diagram you described, there is a hydroxyl group (-OH) attached to a carbon atom, so this option is a possibility.

3. Alkane: An alkane is a saturated hydrocarbon consisting of only single bonds. However, in the diagram, there is a double bond between the carbon and oxygen atoms, which eliminates this option.

4. Amine: An amine is characterized by the presence of a nitrogen atom bonded to one or more alkyl or aryl groups. The diagram you shared does not indicate the presence of a nitrogen atom, so this option can be eliminated.

Considering the analysis above, we can determine that the structure you described is an alcohol.

Please note that it is essential to have a visual representation or the full chemical formula to make an accurate identification.