How do you solve the quadratic formula

9 over 8 - 2 =5 over x^2

9/8 - 2 = 5/x^2

-7/8 = 5/x^2

Multiply both sides by x^2.

-7/8 x^2 = 5

Multiply both sides by - 8/7.

x^2 = -40/7

x = √(-40/7)

Thank you so much for your help

To solve the quadratic equation, we need to get the equation in the standard form: ax^2 + bx + c = 0.

Let's start by rewriting the equation given:

(9/8) - 2 = 5/(x^2)

First, let's simplify the left side of the equation by finding a common denominator:

(9/8) - (16/8) = 5/(x^2)

Now, we can combine the fractions on the left side:

(-7/8) = 5/(x^2)

Next, we can cross-multiply to eliminate the fractions:

-7 * (x^2) = 8 * 5

Simplifying further:

-7x^2 = 40

To continue solving this equation, we need to isolate x^2. Divide both sides of the equation by -7:

x^2 = 40/-7

Simplifying:

x^2 = -40/7

Now, take the square root of both sides of the equation to solve for x:

x = ± (√(-40/7))

At this point, we encounter a bit of a challenge because the discriminant (the expression inside the square root symbol) is negative. This means that the quadratic equation has no real solutions. If you are allowed to work with complex numbers, you can express the answer as x = ± (√(40/7)i), where i represents the imaginary unit.