Two ions which have a simlar shape are?
a. CO32- and SO32-
b. OH- and SO32-
c. PO33- and NO3-
d. SO32- and PO33-
e. CO32- and PO33-
I think (a) not sure plez expalin to me
The right answer is b. OH- and SO32-
To determine which two ions have a similar shape, you can look at their Lewis dot structures. The Lewis dot structure represents the arrangement of atoms and lone pairs in a molecule or ion.
In option (a), CO32- and SO32-, both ions are polyatomic ions with a negative charge.
To find the shape of CO32-, we start by determining the central atom. In this case, carbon is the central atom, surrounded by three oxygen atoms. Carbon has four valence electrons, and each oxygen atom has six valence electrons. To achieve an octet or stable configuration, carbon will share electrons with each oxygen atom, resulting in three double bonds. The Lewis dot structure is:
O O
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O=C=O^2- (double bond)
The shape of CO32- is trigonal planar, meaning it has a flat, triangular shape with the central carbon atom in the center and the three oxygen atoms surrounding it in a plane.
Now let's look at SO32-. To find the shape, we identify the central atom, which is sulfur, surrounded by three oxygen atoms. Sulfur has six valence electrons, and each oxygen atom has six valence electrons. Following the octet rule, sulfur forms one double bond with an oxygen atom and two single bonds with the other two oxygen atoms. The Lewis dot structure is:
O
//
O=S=O^2- (double bond)
\
O
The shape of SO32- is also trigonal planar, with the sulfur atom in the center and the three oxygen atoms around it in a triangular arrangement.
Therefore, the correct answer is option (a) - CO32- and SO32- have a similar shape, both being trigonal planar.