A Canada goose floats with 26.1% of its volume below water. What is the average density of the goose
Where would the goose float if its density was 1.00, .50, or .739
To find the average density of the Canada goose, we need to use the concept of buoyancy and the principle of Archimedes' buoyancy.
Archimedes' principle states that when an object is partially or completely submerged in a fluid (like water), it experiences an upward buoyant force equal to the weight of the fluid it displaces.
In this case, the Canada goose is floating with 26.1% of its volume below water. This means that 73.9% of its volume is above water.
To find the average density, we can set up the equation:
Average Density = (Weight of the Goose) / (Total Volume of the Goose)
The weight of the goose, in this case, is equal to the downward force of the water acting on the submerged portion of the goose. Since the goose is floating, the buoyant force acting upward on the goose is equal to the weight of the goose.
The total volume of the goose is equal to the submerged volume plus the volume above the water.
Let's assume the density of water is ρ_water and the density of the goose is ρ_goose.
Submerged Volume = 26.1% of the total volume
Volume Above Water = 73.9% of the total volume
Total Volume = Submerged Volume + Volume Above Water
Since the average density is equal to the weight divided by the total volume, we can rewrite the equation as:
Average Density = (Weight of the Goose) / (Submerged Volume + Volume Above Water)
Now, to calculate the average density, we need additional information such as the specific gravity or density of the goose.