f(x)=2x^2-x+7 g(x)=x-1
find(f-g)(x) I have an answer of 2x^2+x=6 is this correct or could you say 2x^2+6
To find (f-g)(x), we need to subtract g(x) from f(x).
Given:
f(x) = 2x^2 - x + 7
g(x) = x - 1
Let's substitute f(x) and g(x) into the expression (f-g)(x):
(f - g)(x) = f(x) - g(x)
Substituting the values of f(x) and g(x):
(f - g)(x) = (2x^2 - x + 7) - (x - 1)
Next, we distribute the negative sign to both terms inside the parentheses:
(f - g)(x) = 2x^2 - x + 7 - x + 1
Combining like terms:
(f - g)(x) = 2x^2 - 2x + 8
So, the correct answer should be (f - g)(x) = 2x^2 - 2x + 8.