How many grams of KOH would be necessary to make 200 mL of a 0.15 M solution?
molarity=mole/liter= mass/(molmass*volume)
solve for mass
massingrams=molarity*molmassKOH*.2Liter
To calculate the grams of KOH needed to make a solution, we can use the formula:
Grams = Molarity * Volume * Molecular Weight
First, let's find the molar mass of KOH:
- The atomic weight of potassium (K) is 39.10 g/mol.
- The atomic weight of oxygen (O) is 16.00 g/mol.
- The atomic weight of hydrogen (H) is 1.01 g/mol.
So, the molar mass of KOH is:
(1 * 39.10) + (1 * 16.00) + (1 * 1.01) = 56.11 g/mol.
Next, substitute the given values into the formula:
Grams = 0.15 mol/L * 0.200 L * 56.11 g/mol
Now, calculate the grams:
Grams = 1.6863 g.
Therefore, approximately 1.6863 grams of KOH would be necessary to make 200 mL of a 0.15 M solution.