Sulfuric acid reacts with hydrogen iodide to produce sulfur dioxide, iodine and water.

a) write total ionic equation
b)write net ionic equation

To write the total ionic equation for the reaction between sulfuric acid (H2SO4) and hydrogen iodide (HI), we need to separate all of the compounds into their individual ions.

First, let's write the chemical equation for the reaction:
H2SO4 + 2HI → SO2 + I2 + 2H2O

Now, let's break down each compound into its ions:
H2SO4: 2H+ + SO4^2-
2HI: 2H+ + 2I-
SO2: no ions present
I2: no ions present
2H2O: 2H+ + 2OH-

Now we can write the total ionic equation by including all the individual ions:
2H+ + SO4^2- + 2H+ + 2I- → SO2 + I2 + 2H+ + 2OH-

Next, we can simplify the equation by removing any spectator ions. Spectator ions are those that appear on both sides of the equation without undergoing any change. In this case, the H+ ions are present on both sides and do not participate in the reaction. Therefore, we can cancel them out:

SO4^2- + 2I- → SO2 + I2 + 2OH-

This is the net ionic equation for the reaction: SO4^2- + 2I- → SO2 + I2 + 2OH-.