A 10,000 kg frieight car is rolling along a track at 3.0 m/s. Calculate the time needed for a force of 1000 N to stop the car.

Force = change in momentum/change in time = ma

1000 = (10,000*3)/ change in time
change in time = 10*3 = 30 seconds

force*time= mass*changeinvelocity

1000t=10,000*3
solve for t,in seconds

Well, I must say, this freight car seems to be having quite the roll! Let's calculate the time it takes for the force of 1000 N to bring this car to a halt.

We'll have to use Newton's second law of motion for this one. The formula is F = m * a, where F represents the force, m represents the mass, and a represents the acceleration.

Now, if the freight car is rolling along at a constant velocity of 3.0 m/s, that means there's no acceleration present. But when the force of 1000 N is applied to stop the car, it will cause a deceleration.

Using Newton's second law, we can rearrange the formula to solve for time. It becomes t = m * a / F.

Plugging in the given values, we have:

t = 10,000 kg * (0 m/s^2) / 1000 N.

Oh dear, it seems we've hit a bump in the calculations! Since the car is already at a constant velocity, there would be no acceleration when the force is applied. Thus, we can't calculate a specific time needed to stop the car.

I apologize for not being able to provide a definitive answer. But hey, at least we can appreciate that this freight car won't be making any sudden stops anytime soon!

To calculate the time needed for a force of 1000N to stop the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:

F = m * a

In this case, the force acting on the car is 1000N, and we need to find the acceleration. The car is initially moving at a velocity of 3.0 m/s, but we want to bring it to rest, so the final velocity will be 0 m/s.

We can use the equation for acceleration to find the time needed:

a = (v - u) / t

where:
a = acceleration
v = final velocity
u = initial velocity
t = time

Rearranging the formula to solve for time, we have:

t = (v - u) / a

Given that the final velocity (v) is 0 m/s and the initial velocity (u) is 3.0 m/s, we need to find the acceleration. Rearranging Newton's second law to solve for acceleration, we have:

a = F / m

Plugging in the values:

a = 1000 N / 10,000 kg

Calculating the acceleration:

a = 0.1 m/s^2

Now we can substitute the values into the equation for time:

t = (0 - 3.0) m/s / 0.1 m/s^2

Simplifying the equation further:

t = -3.0 m/s / 0.1 m/s^2

t = -30 seconds

Since time cannot be negative, it means that we made an error in our calculation. The negative sign indicates that our initial assumption was incorrect. We assumed that the force would be enough to stop the car, but it turns out that the force is not sufficient. Therefore, we cannot calculate the time needed for the given force to stop the car.

To calculate the time needed for a force of 1000 N to stop the freight car, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

First, we need to find the acceleration of the freight car when the force of 1000 N is applied to stop it. The formula to calculate acceleration is:

acceleration = force / mass

Given that the mass of the freight car is 10,000 kg and the force is 1000 N:

acceleration = 1000 N / 10,000 kg

acceleration = 0.1 m/s^2

Now that we know the acceleration, we can use the kinematic equation to find the time needed for the car to stop. The appropriate equation is:

final velocity = initial velocity + (acceleration x time)

In this case, the initial velocity of the car is 3.0 m/s, the final velocity is 0 m/s (because the car is stopping), and the acceleration is -0.1 m/s^2 (negative because it acts in the opposite direction of the initial velocity).

0 m/s = 3.0 m/s + (-0.1 m/s^2 x time)

Simplifying the equation:

-3.0 m/s = -0.1 m/s^2 x time

Divide both sides of the equation by -0.1 m/s^2 to solve for time:

time = (-3.0 m/s) / (-0.1 m/s^2)

time = 30 s

Therefore, it will take 30 seconds for a force of 1000 N to stop the freight car.