Did I do this problem right?
Divide.
x^2+4x-48/x+8
Here is how I solved this problem:
x(x+4)-48/x+8
(x+4)-48/8
(x+4)-6
x+4-6
x=2
Is this correct?
Thanks.
Sorry to say this, but looking at that "solution" made me shudder.
the correct way ... assuming you meant:
(x^2+4x-48)/(x+8)
Using long algebraic division, one gets
x - 4 with a remainder of -16
or you can use synthetic division to arrive at the same answer.
(x^2+4x-48)/(x+8) = (x-4) - 16/(x+8)
study this example
http://www.mathsrevision.net/alevel/pages.php?page=1
To determine if you solved the problem correctly, let's go through the steps together.
The problem you solved is:
(x^2 + 4x - 48) / (x + 8)
You factored the numerator correctly:
(x + 8) * (x - 6) / (x + 8)
At this point, you correctly identified that the (x + 8) terms cancel out, which results in:
x - 6
So far, your steps are all correct.
However, you made a mistake in your next step, where you wrote:
x + 4 - 6
The correct step is simply:
x - 6
So, the final answer is x - 6, rather than x + 4 - 6.
Therefore, the correct solution to the problem is x - 6, not x = 2.
I hope this explanation helps! If you have any more questions, feel free to ask.