m<AOB=4x-2,m<BOC=5x+10,m<COD=2x+14
How do you solve the equation? And how do you find the measurement of each of the 3 given angles??
Where tf did you get 360 from??
Your supposed to show the angle to them
To solve the equation and find the measurements of the three given angles, you can follow these steps:
1. Start with the given information about the angles: m<AOB = 4x - 2, m<BOC = 5x + 10, and m<COD = 2x + 14.
2. Since the sum of the angles in a straight line is 180 degrees, you can set up an equation using the given angles:
(4x - 2) + (5x + 10) + (2x + 14) = 180
3. Simplify the equation by combining like terms:
11x + 22 = 180
4. Subtract 22 from both sides of the equation:
11x = 158
5. Divide both sides of the equation by 11 to solve for x:
x = 158 / 11
x ≈ 14.36
6. Now that you have the value of x, you can substitute it back into the expressions for each angle to find their measurements:
- m<AOB = 4x - 2
= 4(14.36) - 2
≈ 57.44 - 2
≈ 55.44 degrees
- m<BOC = 5x + 10
= 5(14.36) + 10
≈ 71.8 + 10
≈ 81.8 degrees
- m<COD = 2x + 14
= 2(14.36) + 14
≈ 28.72 + 14
≈ 42.72 degrees
Therefore, the measurements of the three given angles are approximately:
m<AOB ≈ 55.44 degrees,
m<BOC ≈ 81.8 degrees,
m<COD ≈ 42.72 degrees.
I can only assume that you have a triangle ABC with point O somewhere inside.
Don't your 3 angles form one complete rotation?
so ...
4x-2 + 5x+10 + 2x+14 = 360
I am sure you can solve that for x, then sub the value of x into the expression for each of the angles.
(BTW, the answer does not come out to a "nice" number, describe the figure if I assumed wrong)