solve by the substitution method.
8x+3y=-40
x=48-7y
THE ANSWER SHOULD BE AN ORDERED PAIR. PLEASE HELP ASAP
First you need to replace the x in the original equation with the given variable 48-7y
8(48-7y) + 3y = -40
384 -56y +3y=-40
-56y + 3y = -40 - 384
-53y = -424
-53y/-53=-424/-53
y=8 x=-8
Ordered pair (8,-8)
sorry, I typed ordered pair wrong, the ordered pair is (-8, 8)
To solve the system of equations using the substitution method, we need to substitute the value of x from one equation into the other equation. Let's solve step-by-step:
Given equations:
1) 8x + 3y = -40
2) x = 48 - 7y
Step 1: Substitute the value of x from equation 2 into equation 1.
Replace x in equation 1 with (48 - 7y):
8(48 - 7y) + 3y = -40
Simplify the equation:
384 - 56y + 3y = -40
-53y = -424
y = (-424) / (-53)
y = 8
Step 2: Substitute the value of y into equation 2 to find x.
x = 48 - 7y
x = 48 - 7(8)
x = 48 - 56
x = -8
Therefore, the solution to the system of equations is the ordered pair (-8, 8).