what is the balanced equation of:
Combination reaction: Li2O(s)+H2O(l)-->(?)
I know what a combination reaction is but I don't know how to do it when it is complex like this one.
It forms LiOH.
There are some general rules that go like this.
metal + oxygen = oxide (technically more like a peroxide but the oxide is easier to remember AND under the right conditions it forms the oxide.)
metal oxide + H2O = base.
non-metal + oxygen = non-metallic oxide.
non-metallic oxide + water = acid.
Good
Correct answer
To determine the balanced equation for the combination reaction between Li2O(s) and H2O(l), you need to follow these steps:
Step 1: Identify the elements and their oxidation states in the reactants and products.
In Li2O, lithium (Li) has an oxidation state of +1 and oxygen (O) has -2.
In H2O, hydrogen (H) has an oxidation state of +1 and oxygen (O) has -2.
Step 2: Write the unbalanced equation by placing the reactants and products on opposite sides of the arrow without any coefficients.
Li2O(s) + H2O(l) ->
Step 3: Balance the equation by adding coefficients to the reactants and products so that the number of atoms for each element is the same on both sides of the equation.
Looking at the elements involved, let's start by balancing lithium (Li) first.
Since there are two lithium atoms on the left side (Li2O), we need a coefficient of 2 in front of LiOH on the right side. This gives us:
Li2O(s) + H2O(l) -> 2LiOH
Now let's balance oxygen (O).
On the left side, there are two oxygen atoms (from Li2O) and one oxygen atom (from H2O), totaling three oxygen atoms. To balance the oxygen on the right side, we need a coefficient of 3 in front of H2O. Now our equation becomes:
Li2O(s) + 3H2O(l) -> 2LiOH
Finally, balance hydrogen (H).
On the right side, there are six hydrogen atoms (from 3H2O). To balance the hydrogen on the left side, we need a coefficient of 6 in front of Li2O. The final balanced equation is:
6Li2O(s) + 3H2O(l) -> 2LiOH
So the balanced equation for the combination reaction is:
6Li2O(s) + 3H2O(l) -> 2LiOH