Assuming that 1 gram of aspirin dissolves in 450 ml of water at 10°C, how much aspirin would be lost in 40 ml of water added to the reaction mixture if the mixture were at 10 °C during filtration?
1g X (5ml/450ml)=0.01g
1gx5ml/450ml
How much water is there initially? If none, then, aspirin lost is
1 g x (40 mL/450mL) = ?? grams.
If some water is present initially, then add 40 to it and place the total where 40 is in the above equation.
Well, if I were a gram of aspirin, I'd be quite the troublemaker! Now, let's tackle your question. If 1 gram of aspirin dissolves in 450 ml of water at 10°C, and you have 40 ml of water added to the reaction mixture, we need to find out how much aspirin would be lost in those 40 ml of water.
So, picture this, you have a party (the reaction mixture) and you decide to invite 40 ml of water to the party. But the party is already rockin' at 10°C! The water hops in and starts mingling with the aspirin. Now, since 1 gram of aspirin dissolves in 450 ml of water, it means that 1/450 grams of aspirin dissolve in every 1 ml of water, right?
So, if you have 40 ml of water, you'll have 40/450 grams of aspirin dissolved in that additional water at the party. That's about 0.0889 grams! So, according to my calculations (and some party math), you would lose approximately 0.0889 grams of aspirin in those 40 ml of water.
But hey, remember that I'm just a bot, not a chemist. So, it's best to double-check these calculations with an expert to be sure.
To determine how much aspirin would be lost in the given scenario, we need to first calculate the concentration of the aspirin-water mixture in the original reaction mixture and then use that concentration to find the amount of aspirin in the 40 ml of water.
Given:
- 1 gram of aspirin dissolves in 450 ml of water at 10°C.
To calculate the concentration (C1) of the original aspirin-water mixture, we use the formula:
C1 = mass of solute / volume of solvent
Here, the mass of solute is 1 gram (given), and the volume of solvent is 450 ml.
C1 = 1 gram / 450 ml
Now, assuming no loss occurs during filtration, the aspirin concentration in the original reaction mixture is equal to C1.
To find the amount of aspirin in the 40 ml of water (C2) added during filtration, we will assume that the concentration remains the same (C1). Hence:
C2 = C1 = 1 gram / 450 ml
Now we can calculate the amount of aspirin in the 40 ml of water using the formula:
Amount of aspirin = concentration x volume of solvent
Amount of aspirin = C2 x volume
Substituting the values:
Amount of aspirin = (1 gram / 450 ml) x 40 ml
Simplifying:
Amount of aspirin = (1/450) x 40 gram
Calculating:
Amount of aspirin ≈ 0.0889 gram
Therefore, approximately 0.0889 grams of aspirin would be lost in the 40 ml of water during filtration at 10°C.