I am less than 100.

The sum of my digits is 4.
Half of me is an odd number.

If you multiply me by 2, i become a number greater than 20 and less than 40.

If you multiply me by 6, I end in 8.
If you multiply me by 4, I end in 2.

If less that 100, there are only two numerals. What two numerals add to 4 (1 + 3 or 2 + 2)? Take your pick to fit the remaining information.

If multiplied by to to get > 20 and < 40, then dividing those two numbers by 2 would give you the possible range of the actual number (11-19). Try numbers in that range to find what fits the other two requirements.

> = greater than
< = less than

i am less than 100 the sum of my digits is 4 half of me is an odd number who am i

To find the number that satisfies these conditions, we can break it down step by step.

Condition 1: "I am less than 100."
This means the number we are looking for is a two-digit number.

Condition 2: "The sum of my digits is 4."
Let's consider all the possible combinations of two-digit numbers whose digits add up to 4:
- 13 (1 + 3 = 4)
- 22 (2 + 2 = 4)
- 31 (3 + 1 = 4)
- 40 (4 + 0 = 4)

Condition 3: "Half of me is an odd number."
Let's check the combinations from Condition 2 to find which one fulfills this condition.

For 13:
Half of 13 is 6.5, which is not an odd number, so 13 does not meet the criteria.

For 22:
Half of 22 is 11, which is an odd number. This number meets all the given conditions.

For 31:
Half of 31 is 15.5, which is not an odd number, so 31 does not meet the criteria.

For 40:
Half of 40 is 20, which is not an odd number, so 40 also does not meet the criteria.

Therefore, the number that satisfies all the given conditions is 22.