what is the vapor pressure of ethonal at 75°c?
To find the vapor pressure of ethanol at 75°C, we can refer to a vapor pressure chart or use the Antoine equation. The Antoine equation describes the relationship between vapor pressure and temperature for a specific substance.
The Antoine equation for ethanol is as follows:
log10(P) = A - (B / (T + C))
Where P is the vapor pressure in mmHg, T is the temperature in °C, and A, B, and C are constants specific to ethanol.
To use the Antoine equation, we need to know the values of A, B, and C for ethanol. The values for ethanol are:
A = 8.20417
B = 1642.89
C = 230.3
Now, let's substitute T = 75°C and solve for P:
log10(P) = 8.20417 - (1642.89 / (75 + 230.3))
To find P, we need to take the antilog of both sides of the equation:
P = 10^(8.20417 - (1642.89 / (75 + 230.3)))
Calculating this expression, we find that the vapor pressure of ethanol at 75°C is approximately **201.2 mmHg**.