A rod has a charge of -2.0 ìC. How many electrons must be removed so that the charge becomes +3.3 ìC
how many electrons are in (5.3C)?
To find out how many electrons must be removed from a rod with a charge of -2.0 μC to make the charge +3.3 μC, we need to know the charge on a single electron and then calculate the difference between the desired charge and the current charge.
The charge on a single electron is approximately -1.6 x 10^-19 C.
Firstly, let's convert both charges to coulombs:
-2.0 μC = -2.0 x 10^-6 C
+3.3 μC = +3.3 x 10^-6 C
Next, we calculate the charge difference:
Charge difference = desired charge - current charge
= (+3.3 x 10^-6 C) - (-2.0 x 10^-6 C)
= 3.3 x 10^-6 C + 2.0 x 10^-6 C
= 5.3 x 10^-6 C
To determine the number of electrons associated with this charge difference, we divide it by the charge on a single electron:
Number of electrons = Charge difference / Charge on a single electron
= 5.3 x 10^-6 C / (-1.6 x 10^-19 C)
≈ -3.31 x 10^13 electrons
The negative sign indicates the removal of electrons from the rod, so approximately 3.31 x 10^13 electrons must be removed to change the charge from -2.0 μC to +3.3 μC.