how many moles of carbon dioxide will be produced when 2.8 moles of oxygen react (consider the combustion of ethylene:

C2H4 + 3 Oxygen2 -->2CO2 +2H2Oxygen

I think Bob Pursley answered this above.

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To determine the number of moles of carbon dioxide produced when 2.8 moles of oxygen react, we need to use the balanced chemical equation for the combustion of ethylene.

The balanced equation is:
C2H4 + 3O2 -> 2CO2 + 2H2O

From the balanced equation, we can see that for every 3 moles of oxygen, 2 moles of carbon dioxide are produced.

We are given 2.8 moles of oxygen, so we can set up a proportion to find the number of moles of carbon dioxide produced:

(2 moles CO2 / 3 moles O2) = (x moles CO2 / 2.8 moles O2)

To solve for x, we can cross multiply and then divide:
2 moles CO2 * 2.8 moles O2 = 3 moles O2 * x moles CO2
5.6 moles CO2 = 3 moles O2 * x moles CO2

Dividing both sides by 3 moles O2:
5.6 moles CO2 / 3 moles O2 = x moles CO2

Therefore, the number of moles of carbon dioxide produced when 2.8 moles of oxygen react is approximately 1.87 moles.