Automobile batteries contain sulfuric acid. Calculate the number of grams of sulfuric acid in 0.500L of battery acid if the solution has a density of 1.28g/mL and is 38% H2SO4 (small numbers) by mass?
Can you please answer this for me?
density = 1.28 g/mL
mass of 1 L is 1.28 g/mL x 1000 mL = ??
?? g x 0.38 = grams H2SO4 in the 1 L
Now calculate mass in 0.5 L.
Post your work if you get stuck.
I am sorry, but that seems easy until I try it..
Do I start with 1.28g/mL and x by 1000, then take that answer and x by 0.38g H2SO4.
I just don't know how to set this up. Sorry, that is why I am asking for help.
Yes.
1.28 x 1000 x 0.38 x 0.5L/1L = grams of 38% stuff in 1/2 liter.
how do you convert g/mL
To convert grams per milliliter (g/mL) to grams per liter (g/L), you need to multiply the g/mL value by 1000.
For example, if you have a density of 1.28 g/mL, you can convert it to g/L by multiplying it by 1000:
1.28 g/mL x 1000 = 1280 g/L
This means that there are 1280 grams of the substance in every liter of the solution.