Sorry, another question.
A camper van with a mass of 2500kg has a maximum driving force of 2650N.
The camper van drives along a straight, level road at a constant speed of 90 kilometres per hour. At this speed, air resistance is 2000N and the frction between the tyres and road is 500N
i) What force is the engine exerting?
I have done 2650 - 2500 = 150N but I think this is wrong.
b) A strong headwind begins blowing with a force of 200 N. The van slows down. Calculate it's deceleration.
What I think is using the equation F = m x a, 2700 divided by the mass 2500 gives you 1.08. Then I worked out 2500 divided by the mass 2500 = 1. And the difference between them is the answer?
i) a push force
b)0.08m/s/s
i) To find the force the engine is exerting, you need to consider all the forces acting on the camper van. In this case, you have three forces: driving force, air resistance, and friction.
The driving force provided by the engine is equal to the sum of the air resistance and friction, as these forces oppose the motion of the van. So, the equation becomes:
Driving force = Air resistance + Friction
Given values:
Air resistance = 2000N
Friction = 500N
Replace these values in the equation:
Driving force = 2000N + 500N
Driving force = 2500N
Therefore, the force the engine is exerting is 2500N, not 150N as you initially calculated.
ii) To calculate the deceleration of the van when a headwind of 200N is acting against it, you can indeed use the equation F = m * a.
Given values:
Force (F) = 200N
Mass (m) = 2500kg (same as before)
Rearrange the equation to solve for acceleration (a):
a = F / m
Replace the values:
a = 200N / 2500kg
a = 0.08 m/s^2
Therefore, the deceleration of the van would be 0.08 m/s^2 when the headwind is acting against it.