a room is 18 feet long and 14 feet wide with walls 10 feet high. If one can of paint covers 450 square feet, how many cans of paint would be needed in order to paint the four walls?
[2(18x10) + 2(14x10)]ft^2/450 ft^2/can
= 1.42.
You'd better buy two cans. You will have some left over.
To find out how many cans of paint are needed to paint the four walls of the room, we need to calculate the total area of the four walls and then divide it by the coverage area of one can of paint.
First, let's calculate the area of the walls. Since the room has a rectangular shape, each of the longer walls (18 feet long) will have the same area, and each of the shorter walls (14 feet wide) will also have the same area. The formula to find the area of a rectangle is length multiplied by width.
Area of each long wall = 18 feet * 10 feet = 180 square feet
Area of each short wall = 14 feet * 10 feet = 140 square feet
Since there are two long walls and two short walls, we can calculate the total area of the four walls by adding them up:
Total area of the four walls = 2 * (Area of long wall) + 2 * (Area of short wall)
Total area of the four walls = 2 * 180 square feet + 2 * 140 square feet
Total area of the four walls = 360 square feet + 280 square feet
Total area of the four walls = 640 square feet
Now, let's calculate how many cans of paint are needed. We know that each can of paint covers 450 square feet.
Number of cans of paint needed = Total area of the four walls / Coverage area of one can of paint
Number of cans of paint needed = 640 square feet / 450 square feet
To find the exact number of cans, we need to divide 640 by 450:
Number of cans of paint needed = 1.422...
Since we can't have a fraction of a can, we will need to round up to the next whole number. So, we would need 2 cans of paint to paint the four walls of the room.