__X+3___ is an integer, than X must be?
2
Is your problem?
(x/2) + 3
Ms Sue, the question is :
If x + 3 divided by 2 is an integer, then x must be what
Hmm -- let's try a few numbers --
2 + 3 = 5
5/2 = 2.5
3 + 3 = 6
6/2 = 3
4 + 3 = 7
7/2 = 3.5
5 + 3 = 8
8/2 = 4
What do you think?
To determine the possible values of X, you need to consider the given condition that the expression __X+3___ is an integer.
In the expression __X+3___, the underscore represents a fraction or a division symbol.
For the expression to be an integer, the numerator (X) must be divisible by the denominator (3). This means that X must be a multiple of 3.
Therefore, the possible values of X that would make the expression an integer are any number that is a multiple of 3, such as -6, -3, 0, 3, 6, and so on.
In this particular case, if X is 2, the expression __2+3___ equals 5/3, which is not an integer. So, X=2 does not satisfy the condition.