__X+3___ is an integer, than X must be?

2

Is your problem?

(x/2) + 3

Ms Sue, the question is :

If x + 3 divided by 2 is an integer, then x must be what

Hmm -- let's try a few numbers --

2 + 3 = 5
5/2 = 2.5

3 + 3 = 6
6/2 = 3

4 + 3 = 7
7/2 = 3.5

5 + 3 = 8
8/2 = 4

What do you think?

To determine the possible values of X, you need to consider the given condition that the expression __X+3___ is an integer.

In the expression __X+3___, the underscore represents a fraction or a division symbol.

For the expression to be an integer, the numerator (X) must be divisible by the denominator (3). This means that X must be a multiple of 3.

Therefore, the possible values of X that would make the expression an integer are any number that is a multiple of 3, such as -6, -3, 0, 3, 6, and so on.

In this particular case, if X is 2, the expression __2+3___ equals 5/3, which is not an integer. So, X=2 does not satisfy the condition.