A proton moving in a magnetic field experiences a magnetic force of 17 N at 26o at one instant in time. At the same instant in time, an electron moving with the same speed experiences the same magnetic field. Compare the magnetic force experienced by the electron to that of the proton.
Force depends upon charge. They have equal and opposite charges
q = +e and -e. The magnetic forces (q v X B) will be equal and opposite also.
To compare the magnetic force experienced by the electron to that of the proton, we can use the formula for magnetic force on a charged particle moving in a magnetic field, which is given by:
F = qvBsinθ
Where:
F is the magnetic force
q is the charge of the particle
v is the velocity of the particle
B is the magnetic field strength
θ is the angle between the velocity vector of the particle and the magnetic field vector.
In this case, we are told that the proton experiences a magnetic force of 17 N at an angle of 26°. We are also told that the electron is moving with the same speed in the same magnetic field. However, we need to know the charges of the proton and electron to determine the magnetic force on the electron.
The charge of a proton is +1.6 x 10^-19 C, and the charge of an electron is -1.6 x 10^-19 C. Thus, the magnitudes of the charges are the same, but the sign is different.
Since the magnitude of the magnetic force is directly proportional to the charge, we can conclude that the electron will experience the same magnitude of magnetic force as the proton. However, since the charge of the electron is negative, the direction of the force on the electron will be opposite to that of the proton.
In summary, the electron will experience the same magnitude of magnetic force (17 N) as the proton, but the direction of the force will be opposite.