how to write a net ionic equation of CaS+CuCl2
Cu^+2(aq) + S^-2(aq) ==> CuS(s)
I dont understand how you got that answer. can you pls explain
To write the net ionic equation for the reaction between CaS and CuCl2, we need to first write the balanced molecular equation. The molecular equation shows the reactants and products with their respective chemical formulas.
The chemical formula for calcium sulfide is CaS, and the chemical formula for copper(II) chloride is CuCl2.
The balanced molecular equation would be:
CaS + CuCl2 -> CaCl2 + CuS
Now, let's break down the balanced molecular equation into its ionic components. This is called the complete ionic equation.
CaS dissociates into Ca^2+ and S^2- ions, while CuCl2 dissociates into Cu^2+ and 2 Cl^- ions.
The complete ionic equation would be:
Ca^2+ + S^2- + Cu^2+ + 2 Cl^- -> Ca^2+ + 2 Cl^- + CuS
Finally, the net ionic equation is obtained by eliminating the spectator ions, which are the ions that are present on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are the Ca^2+ and the 2 Cl^- ions.
The net ionic equation for CaS + CuCl2 is:
S^2- + Cu^2+ -> CuS