How many milliliters of NH3 (at STP) are needed to react with 45.0 mL of NO2 (at STP) according to the equation.

Can someone please... help me?

8NO2 (g) + 6NH3 (g) --> 7N2) (g) + 9H2O (g)
IS this help?

a) 45.0 mL
b) 27.5 mL
c) 33.8 mL
d) 60.0 mL

I got C). 33.75 or 33.8. Use Spectrometry. You have 45.0ml of NO2 right. Convert that to Liters so you get .045L. Since its at STP convert .045L to moles using 22.4 L/mol.

(.002 moles of NO2)[(6 moles of NH3)/(8 moles of NO2)] = .0015 mole of NH3

use 22.4 L/mol to convert it to L and multiply it by 1000 to convert to milliliters.

Hope that helps.

Amphee is correct but let me introduce both of you to a shortcut that can be used WHEN ALL OF THE MATERIALS ARE GASES.

The rationale first:
Since you divide by 22.4 to convert to moles, then multiply by 22.4 to convert back to volume, you can omit both of those steps and simply use the coefficients as the following:
45 mL NO x (6 mols NH3/8 moles NO) = 33.75 mL NH3.

Thank you so much both of you. It really help me to understand. :)

To find the answer, we need to use the stoichiometry, which is the relationship between the coefficients of the balanced chemical equation. In this case, the balanced equation is:

8NO2 (g) + 6NH3 (g) --> 7N2 (g) + 9H2O (g)

The stoichiometric ratio shows that 8 moles of NO2 react with 6 moles of NH3. We can use this ratio to convert the volume of NO2 to the volume of NH3.

First, let's convert the volume of NO2 to moles. We know that at STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L. Therefore, 45.0 mL of NO2 is equal to (45.0 mL / 1000 mL/L) * (1 L/1000 mL) * (1 mol/22.4 L) = 0.0002 mol.

Now, using the stoichiometric ratio, we can calculate the moles of NH3 needed. For every 8 moles of NO2, we need 6 moles of NH3. So:

0.0002 mol NO2 * (6 mol NH3 / 8 mol NO2) = 0.00015 mol NH3

Finally, we convert the moles of NH3 to milliliters. Again, at STP, 1 mole of any gas occupies 22.4 L, so:

0.00015 mol NH3 * (22.4 L/mol) * (1000 mL/L) = 3.36 mL NH3

Therefore, the answer is approximately 3.36 mL. However, none of the answer choices provided match this value.